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What is the value of \(\left(16^{-\frac{3}{4}}\right)\cdot8^{\frac{2}{3}}\)?\(\left(16^{-\frac{3}{4}}\right)\cdot8^{\frac{2}{3}}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{1}{2}\)\(\frac{1}{2}\)
Here \(16^{-\frac{3}{4}}=(2^{4})^{-\frac{3}{4}}=2^{-3}\) and \(8^{\frac{2}{3}}=(2^{3})^{\frac{2}{3}}=2^{2}\), so the value is \(2^{-1}=\frac{1}{2}\). In exams, multiply powers of powers.\(16^{-\frac{3}{4}}=(2^{4})^{-\frac{3}{4}}=2^{-3}\) और \(8^{\frac{2}{3}}=(2^{3})^{\frac{2}{3}}=2^{2}\), इसलिए मान \(2^{-1}=\frac{1}{2}\) है। परीक्षा में घात के ऊपर घात को गुणा करें।
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