(\left\(16^{-\frac{3}{4}}\right\)\cdot8^{\frac{2}{3}}) का मान क्या है?
What is the value of (\left\(16^{-\frac{3}{4}}\right\)\cdot8^{\frac{2}{3}})?
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{2}\)
Concept
Here (16^{-\frac{3}{4}}=\(2^{4}\)^{-\frac{3}{4}}=2^{-3}) and (8^{\frac{2}{3}}=\(2^{3}\)^{\frac{2}{3}}=2^{2}), so the value is \(2^{-1}=\frac{1}{2}\). In exams, multiply powers of powers.
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\). Here (16^{-\frac{3}{4}}=\(2^{4}\)^{-\frac{3}{4}}=2^{-3}) and (8^{\frac{2}{3}}=\(2^{3}\)^{\frac{2}{3}}=2^{2}), so the value is \(2^{-1}=\frac{1}{2}\). In exams, multiply powers of powers.
Exam Tip
(16^{-\frac{3}{4}}=\(2^{4}\)^{-\frac{3}{4}}=2^{-3}) और (8^{\frac{2}{3}}=\(2^{3}\)^{\frac{2}{3}}=2^{2}), इसलिए मान \(2^{-1}=\frac{1}{2}\) है। परीक्षा में घात के ऊपर घात को गुणा करें।
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