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What is the smallest number which leaves remainder (0) when divided by (45), (54), and (72)?

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Answer and explanation

Correct answer: (1080)

Step 1: The smallest such number is the LCM of the three numbers. Step 2: (45=3^2\times 5), (54=2\times 3^3), and (72=2^3\times 3^2). The LCM is (2^3\times 3^3\times 5=1080). Step 3: Remainder (0) means exact divisibility by all numbers.

Related tags

LcmDivisibilityPrime Factorisation

Frequently asked questions

What is the correct answer to this question?

(1080)

Why is this the correct answer?

Step 1: The smallest such number is the LCM of the three numbers. Step 2: (45=3^2\times 5), (54=2\times 3^3), and (72=2^3\times 3^2). The LCM is (2^3\times 3^3\times 5=1080). Step 3: Remainder (0) means exact divisibility by all numbers.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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