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What is the smallest number that leaves remainder (13) when divided by (42), (56), and (70)?
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Answer and explanation
Correct answer: (293)
Step 1: Subtracting (13) makes the number divisible by (42), (56), and (70). Step 2: Their LCM is (280), so the smallest number is (280+13=293). Step 3: In common-remainder questions, add the remainder at the end.
Frequently asked questions
What is the correct answer to this question?
(293)
Why is this the correct answer?
Step 1: Subtracting (13) makes the number divisible by (42), (56), and (70). Step 2: Their LCM is (280), so the smallest number is (280+13=293). Step 3: In common-remainder questions, add the remainder at the end.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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