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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationExpertLevel 12
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What is the smallest number exactly divisible by (121), (144), and (250)?

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Answer and explanation

Correct answer: (2178000)

Step 1: The smallest number exactly divisible by all is the LCM. Step 2: (121=11^2), (144=2^4\times3^2), and (250=2\times5^3), so LCM (=2^4\times3^2\times5^3\times11^2=2178000). Step 3: Multiply the highest powers carefully.

Related tags

Real-NumbersLcmDivisibility

Frequently asked questions

What is the correct answer to this question?

(2178000)

Why is this the correct answer?

Step 1: The smallest number exactly divisible by all is the LCM. Step 2: (121=11^2), (144=2^4\times3^2), and (250=2\times5^3), so LCM (=2^4\times3^2\times5^3\times11^2=2178000). Step 3: Multiply the highest powers carefully.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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  5. 5What is the LCM of (40) and (60)?
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