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For \(p,q\neq 0\), what is the simplified form of \(\left(\frac{p^{-5}q^{4}}{p^{-1}q^{-2}}\right)^{-2}\)?

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Answer and explanation

Correct answer: \(p^{8}q^{-12}\)

Using the quotient rule for exponents, \(\frac{p^{-5}q^4}{p^{-1}q^{-2}}=p^{-5-(-1)}q^{4-(-2)}=p^{-4}q^6\). Applying \((a^m)^n=a^{mn}\), we get \((p^{-4}q^6)^{-2}=p^8q^{-12}\), so option A is correct. Option B results from mishandling the signs while multiplying the exponents by the outer \(-2\). Exam tip: subtract exponents when dividing like bases, then multiply by the outside exponent.

Related tags

Laws Of ExponentsNegative ExponentsQuotient RulePowers Of Monomials

Frequently asked questions

What is the correct answer to this question?

\(p^{8}q^{-12}\)

Why is this the correct answer?

Using the quotient rule for exponents, \(\frac{p^{-5}q^4}{p^{-1}q^{-2}}=p^{-5-(-1)}q^{4-(-2)}=p^{-4}q^6\). Applying \((a^m)^n=a^{mn}\), we get \((p^{-4}q^6)^{-2}=p^8q^{-12}\), so option A is correct. Option B results from mishandling the signs while multiplying the exponents by the outer \(-2\). Exam tip: subtract exponents when dividing like bases, then multiply by the outside exponent.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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