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What is the simplified form of \(\left(\frac{9r^{-4}s^{3}}{81r^{2}s^{-5}}\right)^{-1}\)?
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Answer and explanation
Correct answer: \(9r^{6}s^{-8}\)
Inside, \(\frac{9r^{-4}s^{3}}{81r^{2}s^{-5}}=\frac{1}{9}r^{-6}s^{8}\). Raising to (-1) gives \(9r^{6}s^{-8}\).
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What is the correct answer to this question?
\(9r^{6}s^{-8}\)
Why is this the correct answer?
Inside, \(\frac{9r^{-4}s^{3}}{81r^{2}s^{-5}}=\frac{1}{9}r^{-6}s^{8}\). Raising to (-1) gives \(9r^{6}s^{-8}\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
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