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What is the simplified form of \(\left(\frac{7r^{-3}s^{2}}{49r^{2}s^{-4}}\right)^{-1}\)?
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Answer and explanation
Correct answer: \(7r^{5}s^{-6}\)
Inside, \(\frac{7r^{-3}s^{2}}{49r^{2}s^{-4}}=\frac{1}{7}r^{-5}s^{6}\). Raising to (-1) gives \(7r^{5}s^{-6}\).
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What is the correct answer to this question?
\(7r^{5}s^{-6}\)
Why is this the correct answer?
Inside, \(\frac{7r^{-3}s^{2}}{49r^{2}s^{-4}}=\frac{1}{7}r^{-5}s^{6}\). Raising to (-1) gives \(7r^{5}s^{-6}\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
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