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What is the simplified form of (\frac{x^{-3}-y^{-3}}{x^{-1}-y^{-1}}), where (x\neq0), (y\neq0), and (x\neq y)?

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Answer and explanation

Correct answer: (\frac{x^{2}+xy+y^{2}}{x^{2}y^{2}})

The numerator is (\frac{y^{3}-x^{3}}{x^{3}y^{3}}), and the denominator is (\frac{y-x}{xy}). Division gives (\frac{x^{2}+xy+y^{2}}{x^{2}y^{2}}).

Related tags

Negative ExponentsAlgebraic SimplificationExpert

Frequently asked questions

What is the correct answer to this question?

(\frac{x^{2}+xy+y^{2}}{x^{2}y^{2}})

Why is this the correct answer?

The numerator is (\frac{y^{3}-x^{3}}{x^{3}y^{3}}), and the denominator is (\frac{y-x}{xy}). Division gives (\frac{x^{2}+xy+y^{2}}{x^{2}y^{2}}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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