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What is the correct intersection of \(4x+y=11\) and \(x-y=1\)?रेखाएं \(4x+y=11\) और \(x-y=1\) का सही प्रतिच्छेद कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\left(\frac{12}{5},\frac{7}{5}\right)\)\(\left(\frac{12}{5},\frac{7}{5}\right)\)
Putting \(y=x-1\) gives \(4x+x-1=11\), so \(x=\frac{12}{5}\) and \(y=\frac{7}{5}\). Fractional coordinates can also be graphical solutions.\(y=x-1\) रखने पर \(4x+x-1=11\), इसलिए \(x=\frac{12}{5}\) और \(y=\frac{7}{5}\)। ग्राफ में भिन्न निर्देशांक भी समाधान हो सकते हैं।
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