समीकरण \(x^2-2ux+u^2+7u=0\) के वास्तविक मूलों के लिए (u) पर क्या शर्त है?

What condition on (u) is needed for real roots of \(x^2-2ux+u^2+7u=0\)?

Explanation opens after your attempt
Correct Answer

A. \(u\le0\)

Step 1

Concept

For real roots, \(D\ge0\) is needed. Here (D=4u-2-4\(u^2+7u\)=-28u), so \(u\le0\).

Step 2

Why this answer is correct

The correct answer is A. \(u\le0\). For real roots, \(D\ge0\) is needed. Here (D=4u-2-4\(u^2+7u\)=-28u), so \(u\le0\).

Step 3

Exam Tip

वास्तविक मूलों के लिए \(D\ge0\) चाहिए। यहाँ (D=4u-2-4\(u^2+7u\)=-28u), इसलिए \(u\le0\)।

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समीकरण \(x^2-2ux+u^2+7u=0\) के वास्तविक मूलों के लिए (u) पर क्या शर्त है? / What condition on (u) is needed for real roots of \(x^2-2ux+u^2+7u=0\)?

Correct Answer: A. \(u\le0\). Explanation: वास्तविक मूलों के लिए \(D\ge0\) चाहिए। यहाँ (D=4u-2-4\(u^2+7u\)=-28u), इसलिए \(u\le0\)। / For real roots, \(D\ge0\) is needed. Here (D=4u-2-4\(u^2+7u\)=-28u), so \(u\le0\).

Which concept should I revise for this Mathematics MCQ?

For real roots, \(D\ge0\) is needed. Here (D=4u-2-4\(u^2+7u\)=-28u), so \(u\le0\).

What exam hint can help solve this Mathematics question?

वास्तविक मूलों के लिए \(D\ge0\) चाहिए। यहाँ (D=4u-2-4\(u^2+7u\)=-28u), इसलिए \(u\le0\)।