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What are the solutions of (\frac{1}{x}+x=\frac{50}{7}), (x\neq0)?(\frac{1}{x}+x=\frac{50}{7}), (x\neq0), के हल क्या हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=7,\frac{1}{7})(x=7,\frac{1}{7})
(7x^2-50x+7=(7x-1)(x-7)), so (x=\frac{1}{7}) and (7). In exams, check whether obtained roots are valid in the original equation.(7x^2-50x+7=(7x-1)(x-7)), इसलिए (x=\frac{1}{7}) और (7) हैं। परीक्षा में प्राप्त हल मूल समीकरण में मान्य हैं या नहीं जांचें।
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