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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationEasyLevel 12
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Two ropes of (66) m and (110) m are to be cut into equal pieces of maximum length. What will be the length of each piece?

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Answer and explanation

Correct answer: (22) m

Step 1: For maximum equal length, find the HCF of (66) and (110). Step 2: (66=2\times3\times11) and (110=2\times5\times11). Step 3: The common part is (2\times11=22), so each piece will be (22) m long.

Related tags

Real-NumbersHcfApplication

Frequently asked questions

What is the correct answer to this question?

(22) m

Why is this the correct answer?

Step 1: For maximum equal length, find the HCF of (66) and (110). Step 2: (66=2\times3\times11) and (110=2\times5\times11). Step 3: The common part is (2\times11=22), so each piece will be (22) m long.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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