Two numbers are (a=2^5\times 3^2\times 5) and (b=2^3\times 3^4\times 5^2). What is the value of (\frac{\text{LCM}}{\text{HCF}})?
Answer and explanation
Correct answer: (2^2\times 3^2\times 5)
Step 1: The HCF is (2^3\times 3^2\times 5) and the LCM is (2^5\times 3^4\times 5^2). Step 2: On division, subtract exponents, so (\frac{\text{LCM}}{\text{HCF}}=2^2\times 3^2\times 5). Step 3: In such ratios, subtract smaller exponents from larger exponents.
Frequently asked questions
What is the correct answer to this question?
(2^2\times 3^2\times 5)
Why is this the correct answer?
Step 1: The HCF is (2^3\times 3^2\times 5) and the LCM is (2^5\times 3^4\times 5^2). Step 2: On division, subtract exponents, so (\frac{\text{LCM}}{\text{HCF}}=2^2\times 3^2\times 5). Step 3: In such ratios, subtract smaller exponents from larger exponents.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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