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Two numbers are (180) and (252). What is their HCF in prime factor form?

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Answer and explanation

Correct answer: (2^2\times3^2)

Step 1: Write both numbers in prime factor form. Step 2: (180=2^2\times3^2\times5) and (252=2^2\times3^2\times7), so the common smaller powers give (2^2\times3^2). Step 3: Do not include non-common factors like (5) or (7) in HCF.

Related tags

Real-NumbersHcfPrime-Factor-Form

Frequently asked questions

What is the correct answer to this question?

(2^2\times3^2)

Why is this the correct answer?

Step 1: Write both numbers in prime factor form. Step 2: (180=2^2\times3^2\times5) and (252=2^2\times3^2\times7), so the common smaller powers give (2^2\times3^2). Step 3: Do not include non-common factors like (5) or (7) in HCF.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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