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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationHardLevel 10
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Three bells ring at intervals of (18), (24), and (30) seconds respectively. If they ring together now, after how many seconds will they ring together again?

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Answer and explanation

Correct answer: (360)

Step 1: The next common ringing time is the LCM of the intervals. Step 2: (18=2\times3^2), (24=2^3\times3), and (30=2\times3\times5), so LCM (=2^3\times3^2\times5=360). Step 3: For repeated time events, use LCM.

Related tags

Real-NumbersLcmTime-Interval

Frequently asked questions

What is the correct answer to this question?

(360)

Why is this the correct answer?

Step 1: The next common ringing time is the LCM of the intervals. Step 2: (18=2\times3^2), (24=2^3\times3), and (30=2\times3\times5), so LCM (=2^3\times3^2\times5=360). Step 3: For repeated time events, use LCM.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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  1. 1If the product of two numbers is 3780 and their LCM is 315, what is their HCF?
  2. 2What is the HCF of (18) and (24) using prime factorisation?
  3. 3What is the LCM of (18) and (24) using prime factorisation?
  4. 4What is the HCF of (40) and (60)?
  5. 5What is the LCM of (40) and (60)?
  6. 6What will be the HCF of (45) and (75)?
  7. 7What will be the LCM of (45) and (75)?
  8. 8Which is the HCF of (32) and (48)?
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