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The sum of three consecutive terms of an AP is 60. Which term among them must be 20?

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Answer and explanation

Correct answer: Second (middle) term

Write three consecutive AP terms as \(a-d, a, a+d\). Their sum is \(3a=60\), so the middle term is \(a=20\). The first and third terms depend on \(d\). Exam tip: the sum of three consecutive AP terms is always three times the middle term.

Related tags

Arithmetic ProgressionAp PropertiesConsecutive TermsWord ProblemsClass 10 Mathematics

Frequently asked questions

What is the correct answer to this question?

Second (middle) term

Why is this the correct answer?

Write three consecutive AP terms as \(a-d, a, a+d\). Their sum is \(3a=60\), so the middle term is \(a=20\). The first and third terms depend on \(d\). Exam tip: the sum of three consecutive AP terms is always three times the middle term.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Word problems based on APs.

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