0 reads0 ratings0 helpful
The prime factorisations of three numbers are (2^5\times3^2\times5), (2^3\times3^4\times7), and (2^4\times3\times11). What will be their HCF?
Advertisement
Answer and explanation
Correct answer: (2^3\times3)
Step 1: HCF of three numbers includes only primes common to all three. Step 2: (2) and (3) are common, with smallest powers (2^3) and (3). Step 3: Do not include a prime that is not present in every number.
Frequently asked questions
What is the correct answer to this question?
(2^3\times3)
Why is this the correct answer?
Step 1: HCF of three numbers includes only primes common to all three. Step 2: (2) and (3) are common, with smallest powers (2^3) and (3). Step 3: Do not include a prime that is not present in every number.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement