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The prime factorisations of three numbers are (2^3\times3^4\times13), (2^5\times3^2\times5^2), and (2^2\times3^5\times7). What will be their LCM?
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Answer and explanation
Correct answer: (2^5\times3^5\times5^2\times7\times13)
Step 1: LCM takes the highest power of every prime present. Step 2: The highest powers are (2^5), (3^5), (5^2), (7), and (13). Step 3: A prime appearing in only one number must also be included.
Frequently asked questions
What is the correct answer to this question?
(2^5\times3^5\times5^2\times7\times13)
Why is this the correct answer?
Step 1: LCM takes the highest power of every prime present. Step 2: The highest powers are (2^5), (3^5), (5^2), (7), and (13). Step 3: A prime appearing in only one number must also be included.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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