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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationEasyLevel 11
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The prime factorisation of a number is (2^3\times3^2\times5). What is the number?

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Answer and explanation

Correct answer: (360)

Step 1: First evaluate the powers: (2^3=8) and (3^2=9). Step 2: Now (8\times9\times5=360). Step 3: While forming a number from factorisation, simplify powers first and then multiply.

Related tags

Real-NumbersPrime-FactorisationBasic

Frequently asked questions

What is the correct answer to this question?

(360)

Why is this the correct answer?

Step 1: First evaluate the powers: (2^3=8) and (3^2=9). Step 2: Now (8\times9\times5=360). Step 3: While forming a number from factorisation, simplify powers first and then multiply.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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