0 reads0 ratings0 helpful
The HCF of two numbers is (48) and their LCM is (2112). How many unordered pairs of such numbers are possible?
Advertisement
Answer and explanation
Correct answer: (4)
Step 1: Let the numbers be (48m) and (48n), where (m) and (n) are coprime. Step 2: (48mn=2112), so (mn=44=2^2\times11); the unordered coprime pairs are ((1,44)) and ((4,11)), so the count is (2). Step 3: Do not split the same prime factor into both parts.
Frequently asked questions
What is the correct answer to this question?
(4)
Why is this the correct answer?
Step 1: Let the numbers be (48m) and (48n), where (m) and (n) are coprime. Step 2: (48mn=2112), so (mn=44=2^2\times11); the unordered coprime pairs are ((1,44)) and ((4,11)), so the count is (2). Step 3: Do not split the same prime factor into both parts.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement