The HCF of two numbers is (21) and their LCM is (2310). How many unordered pairs are possible?
Answer and explanation
Correct answer: (4)
Step 1: Let the numbers be (21m) and (21n), where (m) and (n) are coprime. Step 2: (21mn=2310), so (mn=110=2\times5\times11). Three distinct prime factors give (4) unordered coprime pairs. Step 3: Do not count the reversed order again.
Frequently asked questions
What is the correct answer to this question?
(4)
Why is this the correct answer?
Step 1: Let the numbers be (21m) and (21n), where (m) and (n) are coprime. Step 2: (21mn=2310), so (mn=110=2\times5\times11). Three distinct prime factors give (4) unordered coprime pairs. Step 3: Do not count the reversed order again.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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