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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationHardLevel 10
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The HCF of two numbers is (2^2\times3) and their LCM is (2^4\times3^3\times5). If one number is (2^4\times3\times5), what is the other number?

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Answer and explanation

Correct answer: (2^2\times3^3)

Step 1: Product of two numbers equals HCF (\times) LCM. Step 2: The other number is (\frac{(2^2\times3)(2^4\times3^3\times5)}{2^4\times3\times5}=2^2\times3^3). Step 3: While dividing prime forms, subtract powers of the same base.

Related tags

Real-NumbersHcf-LcmUnknown-Number

Frequently asked questions

What is the correct answer to this question?

(2^2\times3^3)

Why is this the correct answer?

Step 1: Product of two numbers equals HCF (\times) LCM. Step 2: The other number is (\frac{(2^2\times3)(2^4\times3^3\times5)}{2^4\times3\times5}=2^2\times3^3). Step 3: While dividing prime forms, subtract powers of the same base.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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