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The first row of an auditorium has (24) seats and each next row has (3) more seats. How many seats are there in (10) rows?

Answer and explanation

Correct answer: 375

The numbers of seats form an AP with first term \(a=24\), common difference \(d=3\), and \(n=10\) terms. Using \(S_n=\frac{n}{2}[2a+(n-1)d]\), we get \(S_{10}=\frac{10}{2}[2(24)+9(3)]=5(75)=375\). Hence, 375 is correct. A value such as 365 can result from an error in using the number of terms or the common difference in the sum formula. Exam tip: check the last term using \((n-1)d\); here, the tenth row has \(51\) seats.

Related tags

Arithmetic ProgressionAp SumWord ProblemsAuditorium SeatsClass 10 MathematicsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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