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The first row of a hall has (12) chairs and each next row has (2) more chairs. If there are (432) chairs in total then how many rows are there?

Answer and explanation

Correct answer: (16)

The direct answer is C: there are 16 rows. The numbers of chairs form an arithmetic progression because each row increases by the same amount, 2. Here the first term is a=12, common difference is d=2, and the total is S_n=432. Use the sum formula: S_n=\frac{n}{2}[2a+(n-1)d]. Substitution gives 432=\frac{n}{2}[24+2(n-1)]=\frac{n}{2}(2n+22)=n(n+11). Thus n^2+11n-432=0. Factoring gives (n-16)(n+27)=0, so n=16 because a number of rows cannot be negative. Option A, 14, gives 14(25)=350 chairs, not 432. Option B, 15, gives 15(26)=390. Option C, 16, gives 16(27)=432 and is correct. Option D, 17, gives 17(28)=476. The common mistake is to use the last term formula without checking the total. First identify the AP, then use the sum formula.

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