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In the proofs of (\sqrt{2}), (\sqrt{3}), and (\sqrt{5}), what becomes impossible at the end?

Answer and explanation

Correct answer: The numerator and denominator of a lowest-form fraction having a common factor

Step 1: At the beginning, the fraction is taken in lowest form. Step 2: At the end, a common factor is found in numerator and denominator. Step 3: This is impossible for a lowest-form fraction, so a contradiction occurs.

Related tags

Common ContradictionIrrationality ProofClass 10Proof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematicsClass 10 Mcq

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