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Class 10MathematicsReal NumbersDecimal expansion of rational numbersExpertLevel 21
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In the decimal expansion of (\frac{1}{2^3\cdot 5^4\cdot 19^2}), how many non-repeating digits appear before the recurring part?

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Answer and explanation

Correct answer: (4)

Since (19^2) remains, the decimal is non-terminating recurring, and the larger exponent among (2) and (5) is (4). In such questions, separate recurrence from the initial delay.

Related tags

PreperiodRecurring-DecimalDenominator-AnalysisExpert

Frequently asked questions

What is the correct answer to this question?

(4)

Why is this the correct answer?

Since (19^2) remains, the decimal is non-terminating recurring, and the larger exponent among (2) and (5) is (4). In such questions, separate recurrence from the initial delay.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Decimal expansion of rational numbers.

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  3. 3Under what condition does (\frac{p}{q}) have a terminating decimal expansion when the fraction is in lowest form?
  4. 4After reducing (\frac{15}{40}), what type of decimal expansion will it have?
  5. 5After at most how many decimal places will the decimal expansion of (\frac{7}{16}) terminate?
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  7. 7Which of the following fractions will give a terminating decimal?
  8. 8Which of the following fractions will give a non-terminating recurring decimal?
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