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In how many maximum equal boxes can (30), (45), and (60) toffees be divided?
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Answer and explanation
Correct answer: (15)
Step 1: For maximum equal boxes, find the HCF of (30), (45), and (60). Step 2: (30=2\times3\times5), (45=3^2\times5), (60=2^2\times3\times5). Step 3: The common part is (3\times5=15), so (15) boxes can be made.
Frequently asked questions
What is the correct answer to this question?
(15)
Why is this the correct answer?
Step 1: For maximum equal boxes, find the HCF of (30), (45), and (60). Step 2: (30=2\times3\times5), (45=3^2\times5), (60=2^2\times3\times5). Step 3: The common part is (3\times5=15), so (15) boxes can be made.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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