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Class 10MathematicsArithmetic Progressions (AP)Word problems based on APsEasy
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In an exam centre, (2) candidates sit at the first desk and (2) more candidates sit at each next desk. How many candidates sit at (10) desks?

Answer and explanation

Correct answer: 110

The numbers of candidates at the desks form an AP: 2, 4, 6, \ldots, 20. Here, \(a=2\), \(d=2\), and \(n=10\). Therefore, \(S_{10}=\frac{10}{2}[2(2)+(10-1)\times2]=5(22)=110\). Hence, 110 candidates can sit at the 10 desks. The option 100 may result from an incorrect addition. Exam tip: in AP word problems, first identify \(a\), \(d\), and \(n\), then apply the formula for \(S_n\).

Related tags

Arithmetic ProgressionAp Word ProblemsSum Of TermsClass 10 MathematicsSequence And SeriesWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap
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