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In a school laboratory (7) instruments are placed on the first day and (3) more instruments are placed each next day. How many instruments are placed in (10) days?

Answer and explanation

Correct answer: 205

The daily numbers of instruments form an arithmetic progression: 7, 10, 13, \ldots. Here, the first term is \(a=7\), the common difference is \(d=3\), and the number of terms is \(n=10\). Therefore, \(S_{10}=\frac{10}{2}[2(7)+(10-1)(3)]=5(14+27)=205\). Hence, 205 instruments are placed in 10 days. An answer such as 200 usually results from using an incorrect number of intervals or an incorrect value of the common difference. Exam tip: identify \(a\), \(d\), and \(n\) before applying the AP sum formula.

Related tags

Arithmetic ProgressionAp Word ProblemsSum Of N TermsMathematics Class 10Sequence And SeriesWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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