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In a school laboratory (12) instruments are placed on the first day and (5) more instruments are placed each next day. On which day will (77) instruments be placed?

Answer and explanation

Correct answer: 14

This forms an arithmetic progression with first term 12 and common difference 5. Hence, \(a_n=12+(n-1)\times5\). Putting \(a_n=77\), we get \(12+5(n-1)=77\), so \(5(n-1)=65\), \(n-1=13\), and \(n=14\). Therefore, 77 instruments will be placed on the 14th day. On the 13th day, there would be only 72 instruments. Exam tip: in AP word problems, identify the first term and common difference, then equate the target value to \(a_n\).

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermLinear SequenceClass 10 MathematicsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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