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In a school (15) new admissions happen on the first day and (3) more admissions happen each next day. How many admissions happen on the (6)th day?

Answer and explanation

Correct answer: 30

The admissions form an arithmetic progression with first term \(a=15\) and common difference \(d=3\). Admissions on the sixth day are \(a_6=a+(6-1)d=15+5\times3=30\). \(33\) would be the number of admissions on the seventh day, so it is a close but incorrect option. Exam tip: Use \(n-1\), not \(n\), when finding the \(n\)th term of an AP.

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermCommon DifferenceClass 10 MathematicsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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