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Class 10MathematicsArithmetic Progressions (AP)Word problems based on APsEasy
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In a parking area the first row can hold (12) cars and each next row can hold (4) more cars. What is the total capacity of (6) rows?

Answer and explanation

Correct answer: 132

The row capacities form the AP \(12, 16, 20, 24, 28, 32\). Here, \(a=12\), \(d=4\), and \(n=6\). Therefore, \(S_6=\frac{6}{2}[2(12)+(6-1)4]=3(44)=132\). Hence, the total capacity is 132 cars. Option 136 can result from an incorrect addition. Exam tip: In AP word problems, first identify \(a\), \(d\), and \(n\), then apply the formula for \(S_n\).

Related tags

Arithmetic ProgressionAp Word ProblemsSum Of ApClass 10 MathematicsParking CapacityWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap
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