In a bank account, (500) rupees are deposited in the first month and (100) rupees more each next month. What is the deposit in the (9)th month?
Answer and explanation
Correct answer: ₹1300
The monthly deposits form an arithmetic progression with first term \(a=500\) and common difference \(d=100\). The ninth term is \(a_9=a+(9-1)d=500+8\times100=1300\). Therefore, the correct deposit is ₹1300. ₹1200 would count only 7 increases, whereas there are 8 increases from the first month to the ninth month. Exam tip: use \(a_n=a+(n-1)d\) to find the \(n\)th term of an AP.
Frequently asked questions
What is the correct answer to this question?
₹1300
Why is this the correct answer?
The monthly deposits form an arithmetic progression with first term \(a=500\) and common difference \(d=100\). The ninth term is \(a_9=a+(9-1)d=500+8\times100=1300\). Therefore, the correct deposit is ₹1300. ₹1200 would count only 7 increases, whereas there are 8 increases from the first month to the ninth month. Exam tip: use \(a_n=a+(n-1)d\) to find the \(n\)th term of an AP.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Word problems based on APs.
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