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In (2^5\times3^3\times7), how many prime factors are there if repetition is counted?
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Answer and explanation
Correct answer: 9
Step 1: To count with repetition, add the exponents. Step 2: (2^5) gives 5, (3^3) gives 3, and (7) gives 1 factor. Step 3: Total (5+3+1=9), so the answer is 9.
Frequently asked questions
What is the correct answer to this question?
9
Why is this the correct answer?
Step 1: To count with repetition, add the exponents. Step 2: (2^5) gives 5, (3^3) gives 3, and (7) gives 1 factor. Step 3: Total (5+3+1=9), so the answer is 9.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.
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