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In (2^4\times3^2\times5), how many prime factors are there if repetition is counted?
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Answer and explanation
Correct answer: 7
Step 1: When repetition is counted, add the exponents. Step 2: (2^4) gives 4 factors, (3^2) gives 2 factors, and (5) gives 1 factor. Step 3: Total (4+2+1=7), so the answer is 7.
Frequently asked questions
What is the correct answer to this question?
7
Why is this the correct answer?
Step 1: When repetition is counted, add the exponents. Step 2: (2^4) gives 4 factors, (3^2) gives 2 factors, and (5) gives 1 factor. Step 3: Total (4+2+1=7), so the answer is 7.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.
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