यदि \(x=\sqrt{23}\) है तो \(x^2+2x\) किस प्रकार की संख्या है?

If \(x=\sqrt{23}\), what type of number is \(x^2+2x\)?

Explanation opens after your attempt
Correct Answer

A. अपरिमेय संख्याIrrational number

Step 1

Concept

\(x^2+2x=23+2\sqrt{23}\). The sum of a rational and an irrational number is irrational.

Step 2

Why this answer is correct

The correct answer is A. अपरिमेय संख्या / Irrational number. \(x^2+2x=23+2\sqrt{23}\). The sum of a rational and an irrational number is irrational.

Step 3

Exam Tip

\(x^2+2x=23+2\sqrt{23}\) है। परिमेय और अपरिमेय का योग अपरिमेय होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{23}\) है तो \(x^2+2x\) किस प्रकार की संख्या है? / If \(x=\sqrt{23}\), what type of number is \(x^2+2x\)?

Correct Answer: A. अपरिमेय संख्या / Irrational number. Explanation: \(x^2+2x=23+2\sqrt{23}\) है। परिमेय और अपरिमेय का योग अपरिमेय होता है। / \(x^2+2x=23+2\sqrt{23}\). The sum of a rational and an irrational number is irrational.

Which concept should I revise for this Mathematics MCQ?

\(x^2+2x=23+2\sqrt{23}\). The sum of a rational and an irrational number is irrational.

What exam hint can help solve this Mathematics question?

\(x^2+2x=23+2\sqrt{23}\) है। परिमेय और अपरिमेय का योग अपरिमेय होता है।