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If (x=2^a\times3^2\times5) and (y=2^4\times3^b\times7) have HCF (2^3\times3^2), which values are possible?
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Answer and explanation
Correct answer: (a=3), (b=2)
Step 1: HCF uses the smaller power of each common prime. Step 2: For (2), the smaller power must be (3), so (a=3) is possible; for (3), (b=2) is possible. Step 3: Check each unknown power separately.
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What is the correct answer to this question?
(a=3), (b=2)
Why is this the correct answer?
Step 1: HCF uses the smaller power of each common prime. Step 2: For (2), the smaller power must be (3), so (a=3) is possible; for (3), (b=2) is possible. Step 3: Check each unknown power separately.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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