If two numbers are (2^3\times 3^2\times 5) and (2^2\times 3^4\times 7), what is the product of their HCF and LCM?
Answer and explanation
Correct answer: (2^5\times 3^6\times 5\times 7)
Step 1: For two numbers, HCF times LCM equals the product of the two numbers. Step 2: Adding exponents gives (2^{3+2}\times 3^{2+4}\times 5\times 7=2^5\times 3^6\times 5\times 7). Step 3: When the product is asked, you need not find HCF and LCM separately.
Frequently asked questions
What is the correct answer to this question?
(2^5\times 3^6\times 5\times 7)
Why is this the correct answer?
Step 1: For two numbers, HCF times LCM equals the product of the two numbers. Step 2: Adding exponents gives (2^{3+2}\times 3^{2+4}\times 5\times 7=2^5\times 3^6\times 5\times 7). Step 3: When the product is asked, you need not find HCF and LCM separately.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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