यदि \(x^2+ax+b=0\) की जड़ें \(\frac{1}{2+\sqrt{3}}\) और \(\frac{1}{2-\sqrt{3}}\) हैं, तो (a) का मान क्या है?
If the roots of \(x^2+ax+b=0\) are \(\frac{1}{2+\sqrt{3}}\) and \(\frac{1}{2-\sqrt{3}}\), what is the value of (a)?
Explanation opens after your attempt
Correct Answer
A. (-4)
Concept
The given roots become \(2-\sqrt{3}\) and \(2+\sqrt{3}\). Their sum is (4), so (a=-4).
Why this answer is correct
The correct answer is A. (-4). The given roots become \(2-\sqrt{3}\) and \(2+\sqrt{3}\). Their sum is (4), so (a=-4).
Exam Tip
दी गई जड़ें \(2-\sqrt{3}\) और \(2+\sqrt{3}\) बनती हैं। उनका योग (4) है, इसलिए (a=-4)।
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