यदि \(x^2-10x+21=0\) के मूल \(\alpha,\beta\) हैं, तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) क्या होगा?
If the roots of \(x^2-10x+21=0\) are \(\alpha,\beta\), what is \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?
Explanation opens after your attempt
A. \( \frac{58}{21}\)
Concept
\(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\), where \(\alpha+\beta=10\) and \(\alpha\beta=21\), so the value is \(\frac{100-42}{21}=\frac{58}{21}\). In exams, convert expressions into sum and product.
Why this answer is correct
The correct answer is A. \( \frac{58}{21}\). \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\), where \(\alpha+\beta=10\) and \(\alpha\beta=21\), so the value is \(\frac{100-42}{21}=\frac{58}{21}\). In exams, convert expressions into sum and product.
Exam Tip
\(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\), जहां \(\alpha+\beta=10\) और \(\alpha\beta=21\), इसलिए मान \(\frac{100-42}{21}=\frac{58}{21}\) है। परीक्षा में अभिव्यक्ति को योग और गुणनफल में बदलें।
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