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If the prime factorisations of two numbers are (2^3\times3^2\times5) and (2^2\times3^3\times7), what is their HCF?
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Answer and explanation
Correct answer: (2^2\times3^2=36)
Step 1: For HCF, take only the common prime factors. Step 2: The common factors are (2) and (3), and the smaller powers are (2^2) and (3^2), so the HCF is (36). Step 3: In exams, remember that HCF uses the minimum powers of common primes.
Frequently asked questions
What is the correct answer to this question?
(2^2\times3^2=36)
Why is this the correct answer?
Step 1: For HCF, take only the common prime factors. Step 2: The common factors are (2) and (3), and the smaller powers are (2^2) and (3^2), so the HCF is (36). Step 3: In exams, remember that HCF uses the minimum powers of common primes.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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