यदि समांतर श्रेढ़ी का (n)वाँ पद \(a_n=2n+1\) है, तो पहले (6) पदों का योग कितना है?

If the (n)th term of an arithmetic progression is \(a_n=2n+1\), what is the sum of the first (6) terms?

Explanation opens after your attempt
Correct Answer

B. (48)

Step 1

Concept

The first (6) terms are (3,5,7,9,11,13), whose sum is (48). When \(a_n\) is given, find the first and last terms.

Step 2

Why this answer is correct

The correct answer is B. (48). The first (6) terms are (3,5,7,9,11,13), whose sum is (48). When \(a_n\) is given, find the first and last terms.

Step 3

Exam Tip

पहले (6) पद (3,5,7,9,11,13) हैं, जिनका योग (48) है। \(a_n\) दिया हो तो पहले और अंतिम पद निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि समांतर श्रेढ़ी का (n)वाँ पद \(a_n=2n+1\) है, तो पहले (6) पदों का योग कितना है? / If the (n)th term of an arithmetic progression is \(a_n=2n+1\), what is the sum of the first (6) terms?

Correct Answer: B. (48). Explanation: पहले (6) पद (3,5,7,9,11,13) हैं, जिनका योग (48) है। \(a_n\) दिया हो तो पहले और अंतिम पद निकालें। / The first (6) terms are (3,5,7,9,11,13), whose sum is (48). When \(a_n\) is given, find the first and last terms.

Which concept should I revise for this Mathematics MCQ?

The first (6) terms are (3,5,7,9,11,13), whose sum is (48). When \(a_n\) is given, find the first and last terms.

What exam hint can help solve this Mathematics question?

पहले (6) पद (3,5,7,9,11,13) हैं, जिनका योग (48) है। \(a_n\) दिया हो तो पहले और अंतिम पद निकालें।