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If the LCM of (196), (225), and (308) is found, how many distinct prime factors will it have?
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Answer and explanation
Correct answer: (5)
Step 1: Prime factorise: (196=2^2\times7^2), (225=3^2\times5^2), and (308=2^2\times7\times11). Step 2: The distinct primes in the LCM are (2), (3), (5), (7), and (11), so there are (5). Step 3: Count distinct prime bases, not powers.
Frequently asked questions
What is the correct answer to this question?
(5)
Why is this the correct answer?
Step 1: Prime factorise: (196=2^2\times7^2), (225=3^2\times5^2), and (308=2^2\times7\times11). Step 2: The distinct primes in the LCM are (2), (3), (5), (7), and (11), so there are (5). Step 3: Count distinct prime bases, not powers.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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