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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationExpertLevel 11
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If the HCF of two numbers is (96) and their LCM is (1248), what is correct about their existence?

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Answer and explanation

Correct answer: Such whole numbers are possible

Step 1: The HCF must exactly divide the LCM. Step 2: (1248\div96=13), which is a whole number, so such whole numbers can exist. Step 3: For existence checks, first test this necessary condition.

Related tags

Real-NumbersHcf-Lcm-Validity

Frequently asked questions

What is the correct answer to this question?

Such whole numbers are possible

Why is this the correct answer?

Step 1: The HCF must exactly divide the LCM. Step 2: (1248\div96=13), which is a whole number, so such whole numbers can exist. Step 3: For existence checks, first test this necessary condition.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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