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If the HCF of two numbers is (64) and their LCM is (5120), what will be the total power of (2) in their product?

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Answer and explanation

Correct answer: (15)

Step 1: (64=2^6) and (5120=2^{10}\times5). Step 2: Product equals HCF times LCM, so the power of (2) is (6+10=16). Step 3: Add exponents when multiplying powers with the same base.

Related tags

Real-NumbersHcf-LcmPrime-Power

Frequently asked questions

What is the correct answer to this question?

(15)

Why is this the correct answer?

Step 1: (64=2^6) and (5120=2^{10}\times5). Step 2: Product equals HCF times LCM, so the power of (2) is (6+10=16). Step 3: Add exponents when multiplying powers with the same base.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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