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Subjects
Class 10MathematicsReal NumbersHCF and LCM using prime factorisationHardLevel 12
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If the HCF of two numbers is (20) and their LCM is (420), what is correct about their existence?

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Answer and explanation

Correct answer: Such two whole numbers are not possible

Step 1: The HCF must be an exact divisor of the LCM. Step 2: (420) is not exactly divisible by (20), so such two whole numbers are not possible. Step 3: Check this condition before trying to form a pair.

Related tags

Real-NumbersHcf-Lcm-Validity

Frequently asked questions

What is the correct answer to this question?

Such two whole numbers are not possible

Why is this the correct answer?

Step 1: The HCF must be an exact divisor of the LCM. Step 2: (420) is not exactly divisible by (20), so such two whole numbers are not possible. Step 3: Check this condition before trying to form a pair.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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  1. 1If the product of two numbers is 3780 and their LCM is 315, what is their HCF?
  2. 2What is the HCF of (18) and (24) using prime factorisation?
  3. 3What is the LCM of (18) and (24) using prime factorisation?
  4. 4What is the HCF of (40) and (60)?
  5. 5What is the LCM of (40) and (60)?
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  7. 7What will be the LCM of (45) and (75)?
  8. 8Which is the HCF of (32) and (48)?
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