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If the HCF of two numbers is (2^3\times3^2) and their LCM is (2^6\times3^5\times5), what will be the total power of (3) in their product?

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Answer and explanation

Correct answer: (7)

Step 1: Product of two numbers equals HCF times LCM. Step 2: The powers of (3) are (2) and (5), so the total power is (7). Step 3: Exponents of the same base add during multiplication.

Related tags

Real-NumbersHcf-LcmPrime-Power

Frequently asked questions

What is the correct answer to this question?

(7)

Why is this the correct answer?

Step 1: Product of two numbers equals HCF times LCM. Step 2: The powers of (3) are (2) and (5), so the total power is (7). Step 3: Exponents of the same base add during multiplication.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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