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If the HCF of (72), (90), and (150) is found, what will be the power of (3)?
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Answer and explanation
Correct answer: (1)
Step 1: Compare the powers of (3). Step 2: (72=2^3\times3^2), (90=2\times3^2\times5), and (150=2\times3\times5^2), so the smallest power is (1). Step 3: HCF uses the smallest power.
Frequently asked questions
What is the correct answer to this question?
(1)
Why is this the correct answer?
Step 1: Compare the powers of (3). Step 2: (72=2^3\times3^2), (90=2\times3^2\times5), and (150=2\times3\times5^2), so the smallest power is (1). Step 3: HCF uses the smallest power.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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