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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationExpertLevel 12
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If the HCF of (221), (323), and (437) is found, what is the correct value?

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Answer and explanation

Correct answer: (1)

Step 1: (221=13\times17), (323=17\times19), and (437=19\times23). Step 2: No prime factor is common to all three numbers, so the HCF is (1). Step 3: Only a factor present in all three numbers is taken.

Related tags

Real-NumbersHcfThree-Numbers

Frequently asked questions

What is the correct answer to this question?

(1)

Why is this the correct answer?

Step 1: (221=13\times17), (323=17\times19), and (437=19\times23). Step 2: No prime factor is common to all three numbers, so the HCF is (1). Step 3: Only a factor present in all three numbers is taken.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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  1. 1If the product of two numbers is 3780 and their LCM is 315, what is their HCF?
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  5. 5What is the LCM of (40) and (60)?
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  8. 8Which is the HCF of (32) and (48)?
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