यदि (p(x)=\sqrt{2}x-2-4x+\sqrt{2}), तो शून्यकों का योग क्या है?
If (p(x)=\sqrt{2}x-2-4x+\sqrt{2}), what is the sum of its zeroes?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{2}\)
Concept
The sum is \(-\frac{b}{a}=\frac{4}{\sqrt{2}}=2\sqrt{2}\). Rationalising the denominator simplifies the answer.
Why this answer is correct
The correct answer is A. \(2\sqrt{2}\). The sum is \(-\frac{b}{a}=\frac{4}{\sqrt{2}}=2\sqrt{2}\). Rationalising the denominator simplifies the answer.
Exam Tip
योग \(-\frac{b}{a}=\frac{4}{\sqrt{2}}=2\sqrt{2}\) है। हर का परिमेयकरण करने से उत्तर सरल होता है।
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